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| BAV199... Silicon Low Leakage Diode * Low-leakage applications * Medium speed switching times * Series pair configuration BAV199 BAV199F 3 D1 D2 1 2 Type BAV199 BAV199F* * Preliminary Package SOT23 TSFP-3 Configuration series series Marking JYs JYs Maximum Ratings at TA = 25C, unless otherwise specified Parameter Symbol VR VRM IF I FSM Value Unit Diode reverse voltage Peak reverse voltage Forward current Non-repetitive peak surge forward current t = 1 s t=1s 80 85 200 4.5 0.5 V mA A Total power dissipation BAV199, TS 31C BAV199F, TS tbd Junction temperature Storage temperature Ptot mW 330 250 Tj T stg 150 -65 ... 150 C 1 Mar-10-2004 BAV199... Thermal Resistance Parameter Symbol RthJS Value 360 tbd Unit Junction - soldering point1) BAV199 BAV199F K/W Electrical Characteristics at TA = 25C, unless otherwise specified Symbol Values Unit Parameter min. typ. max. DC Characteristics 85 V Breakdown voltage V(BR) I(BR) = 100 A Reverse current VR = 75 V VR = 75 V, TA = 150 C Forward voltage IF = 1 mA IF = 10 mA IF = 50 mA IF = 150 mA AC Characteristics Diode capacitance VR = 0 V, f = 1 MHz Reverse recovery time IF = 10 mA, IR = 10 mA, measured at IR = 1mA , RL = 100 Test circuit for reverse recovery time D.U.T. IR VF CT t rr 2 0.6 900 1000 1100 1250 1.5 5 80 nA mV pF s Pulse generator: tp = 10s, D = 0.05, tr = 0.6ns, Ri = 50 Oscillograph F Oscillograph: R = 50, tr = 0.35ns, C 1pF EHN00019 1For calculation of RthJA please refer to Application Note Thermal Resistance 2 Mar-10-2004 BAV199... Reverse current IR = (TA) VR = 70V 10 2 BAV 199 EHB00085 Forward Voltage VF = (TA) IF = Parameter 1.5 V max BAV 199 EHB00088 R nA 10 1 VF 1.0 10 0 F = 150 mA 50 mA 10 mA 10 -1 typ 1 mA 0.1 mA 0.5 10-2 10-3 0 50 100 TA C 150 0 0 50 100 TA C 150 Forward current IF = (VF) TA = 25C 150 BAV 199 EHB00086 Forward current IF = (T S) BAV199 250 mA F mA 200 175 IF 100 150 125 100 typ max 50 75 50 25 0 0 0.5 1.0 V VF 1.5 0 0 15 30 45 60 75 90 105 120 C TS 150 3 Mar-10-2004 BAV199... Permissible Puls Load RthJS = (tp) Permissible Pulse Load IFmax / I FDC = (t p) 10 3 10 2 10 2 I Fmax/IFDC - 10 1 10 0 D = 0,5 0,2 0,1 0,05 0,02 0,01 0,005 0 10 1 D=0 0.005 0.01 0.02 0.05 0.1 0.2 0.5 RthJS 10 -1 -7 10 10 -6 10 -5 10 -4 10 -3 10 -2 s 10 0 10 0 -6 10 10 -5 10 -4 10 -3 10 -2 s 10 0 TP TP 4 Mar-10-2004 |
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